3p^2+3p=23

Solution for 3p^2+3p=23 equation:

3p^2+3p=23

We move all terms to the left:

3p^2+3p-(23)=0

a = 3; b = 3; c = -23;
Δ = b2-4ac
Δ = 32-4·3·(-23)
Δ = 285
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{285}}{2*3}=\frac{-3-\sqrt{285}}{6}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{285}}{2*3}=\frac{-3+\sqrt{285}}{6}
$